Ascientist measures the standard enthalpy change for the following reaction to be 595.8 kj : 2h2o(l)2h2(g) + o2(g) based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of h2o(l) is kj/mol.

The for in the reaction is 297.9 kJ/mol.

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.

The equation that is used to calculate enthalpy change of a reaction is:

For the given chemical reaction:

The equation for the enthalpy change of the above reaction is:

We are given:

Enthalpy of substances present in their standard form are taken to be 0.

Putting values in above equation, we get:

Hence, the for in the reaction is 297.9 kJ/mol.

your answer would be “dry”