The compound ax2 decomposes according to the equation, 2 ax2(g) => 2 ax(g) + x2(g). in one experiment, ax2 was measured at various times, and these data recorded: time (s) {ax2} mol/l 0 0.0500 2.0 0.0448 6.0 0.0300 8.0 0.0249 10.0 0.0209 20.0 0.0088 what is the average rate from 8.0 to 20.0 seconds in mol / l s? use 4 decimal places.

0.001341 mol/L s is the average rate from 8.0 to 20.0 seconds.

Explanation:

Average rate of the reaction =

=Average rate of the reaction during the given time interval.

= Change in concentration of reactant with respect to time.

= Change in time.

=Concentration of reactant at time

=Concentration of reactant at time

So, at the concentration of :

And at the concentration of :

The average rate of the reaction at given interval will be given as:

0.001341 mol/L s is the average rate from 8.0 to 20.0 seconds.

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong