Glass is a notorious source of metal ion contamination. three glass bottles were crushed and sieved to collect 1 mm pieces. to see how much al3+ could be extracted, 210. ml of a 0.05 m solution of the metal-binding compound edta was stirred with 0.50 g of the 1 mm glass particles in a polyethylene flask. the al content of the solution after 2 months was 5.2 μm. the total al content of the glass, measured after completely dissolving some glass in 48 wt% hf with microwave heating, was 0.80 wt%. what fraction of the al was extracted from the glass by edta? (enter your answer to 5 decimal places.)

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

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