In one roasting unit, 1000 kg of an ore concentrate of the composition given below is roasted using excess air ni3s 21% fes 40% sio2 31% h20 8% the roasting unit is heated by oil of composition 85% cand 15% h, the amount of oil is 6.2 % of the weight of the ore. the gases from combustion and roasting mix together and are carried through as flue gases s is converted to so2 the roasted product consists of nio, fe: o, and sio2 and the roasting reactions are given as; ni3s27/2023nio 250 2 2fes2 11/202 fe2o3 4s0 (i) explain how you would increase the kinetics of roasting and hence the production rate (5 marks) (i) calculate: a) weight of roasted product (10 marks) volume of the fuel oil given that its density is 0.89 g/cm2 (5 marks) b) volume of so2 in m2 (5 marks) c) (note: atomic weights are ni 59, fe 56, s 32, o= 16, h - 1 )

Oxidation-reduction reactions (often called "redox" for short) are reactions that involve the transfer of electrons from one species to another. oxidation states, or oxidation numbers, allow chemists to keep track of these electron transfers. in general, one element will lose electrons (oxidation), with the result that it will increase in oxidation number, and another element will gain electrons (reduction), thereby decreasing in oxidation number. the species that is oxidized is called the reducing agent or reductant. the species that is reduced is called the oxidizing agent or oxidant. to sum up: oxidation = increase in oxidation state = loss of electrons = reducing agent reduction = decrease in oxidation state = gain of electrons = oxidizing agent part a which element is oxidized in this reaction? fe2o3+3co→2fe+3co2 enter the elemental symbol. view available hint(s) is oxidized part b which element is reduced in this reaction? 2hcl+2kmno4+3h2c2o4→6co2+2mno2+2kcl+4h2o enter the elemental symbol. view available hint(s) is reduced