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the main component of smog is no2(g). smog is a product that is formed through the following series of intermediate chemical
reactions.
n2(g) + o2(g)—> 2no(g)
2no(g) + o2(g)—> 2no2(g)
non(g) light_» no(g) + o(g)
o2(g)+o(g)—> os(9)
no(g) + o2(g)—> no2(g) + o2(g)
what is the overall chemical equation for smog after the above intermediate reactions are combined?
n2(g)+302(9)+203(g)+20(g) no(g)+ 4no2(g) +203(9)
n2(g) + 302(g) + o2(g)+o() — 9no(g)+3no2(g) + os(g)
16n2(g) + 302(g) → 3n02(0)
n2(g) +202(g) → 2no2(g)

N₂(g) + 2O₂(g) → 2NO₂(g).

Explanation;

Photo-chemical smog is considered to be a new type of air pollution that is basically a mixture of pollutants that are formed when volatile compounds of organic nature (Hydrocarbons) react and Nitrogen oxides  (NOx) react with solar radiations of sun and lead to the formation of photochemical smog that looks like a brown haze in the skies of cities.

pounds (VOCs) react to sunlight, creating a brown haze above cities. It tends to occur more often in summer, because that is when we have the most sunlight.

As mentioned in the question, the formation of smog involves a series of reactions:

N2(g) + O2(g)—>2NO(g)

2NO(g) + O2(g)—>2NO2(g)

NON(g) light_» NO(g) + O(g)

O2(g)+O(g)—>Os(9)

NO(g) + O2(g)—>NO2(g) + O2(g)

If we combine all these chemical equations, it gives an answer as:

N₂(g) + 2O₂(g) → 2NO₂(g).

This is because main components involve in the formation of smog is initial N2 and 2 molecules of O2.

Hope it helps!

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation: