What is the specific latent heat of fusion of ice if it takes 863 kj to convert 4.6 kg of ice into water at 0 c?

Answer : The specific latent heat of fusion of ice is, 187.608 J/g

Explanation :

Formula used :

where,

Q = heat supply = 863 KJ = 863000 J

conversion used : (1 KJ = 1000 J)

m = mass of the substance = 4.6 Kg = 4600 g

conversion used : (1 Kg = 1000 g)

= specific latent heat of fusion = ?

Now put all the given values in the above formula, we get the specific latent heat of fusion of ice.

Therefore, the specific latent heat of fusion of ice is, 187.608 J/g

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

if you're asking what comes out, it's steam.