Liquid octane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . suppose 97. g of octane is mixed with 150. g of oxygen. calculate the maximum mass of water that could be produced by the chemical reaction. round your answer to significant digits.

61 grams

Explanation:

To calculate the number of moles, we use the equation:

The chemical equation for the combustion of octane in oxygen follows the equation:

By stoichiometry of the reaction;

25 moles of oxygen react with 2 moles of octane

4.69 moles of oxygen react with=  moles of octane

Thus, oxygen is the limiting reagent as it limits the formation of product and octane is the excess reagent.

25 moles of oxygen produce 18 moles of water

4.69 moles of oxygen produce=  moles of water.

Mass of water produced=

The maximum mass of water that could be produced by the chemical reaction is 61 grams.

2b2t

explanation:

2b2t