Fe2o3 (molar mass = 159.7 g/mol) reacts with co (molar mass = 28.0 g/mol) according to the equation when 125.6 g of co reacts with excess fe2o3, how many moles of fe (iron) will be produced?

=1.4953 moles

Explanation:

Iron (III) Oxide is reduced by carbon (II) oxide into Iron. According to the following equation, One mole of Fe₂O₃ react with 3 moles of CO to produce  2 moles of Fe. Thus the reaction ratio of CO to Fe₂O₃ is 3:1  

Fe₂O₃₍s₎ + 3CO  → 2Fe₍s₎ + 3CO₂₍g₎

125.6 grams of CO is equivalent to: 125.6g/28.0g/mol

=4.486 moles.

The number of moles of Fe produced by the reaction is:

=(4.486 moles×1)/3

=1.4953 moles

"the periodic table is arranged in order of atomic number."

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