An industrial plant processes its waste water through a sedimentation tank that removes hazardous metals by precipitating them as insoluble carbonate salts. if sodium carbonate is gradually added to the tank, what would be the order of precipitation of the metals, pb2+, cu2+, hg22+, and zn2+ if each is ≈ 1.0 × 10–4 m? ( ksp pbco3 = 7.4 × 10–14, ksp cuco3 = 1.4 × 10–10, ksp hg2co3 = 8.9 × 10–17, and ksp znco3 = 1.4 × 10–11)

the answer to your question is c

it would be a gas formation

(b) which contains higher levels of vitamin b, oranges or spinach?

explanation:

you can eliminate a, c, and d because they are questions based on opinions.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.