Calculate the molar mass of a compound from the following information. you find that the freezing point of benzene is 5.5 degrees c. you then dissolve 1.60 grams of the unknown compound in 20.00 grams of benzene. the freezing point of the solution is found to be 2.8 degrees c. the freezing point depression constant for benzene is 4.3 degrees c/m.

The molar mass (Mm) of the compound is 127.39 g/mole

Explanation:

ΔT = Kf. molality

ΔT = change in temperature = Tfinal - Tinitial = 2.8 - 5.5

Kf = freezing point depression constant = - 4.3 C/m (always negative because temperature is decreasing)

molality = moles of solute/Kg of solvent = mole (n)/(20 x 10^-3 Kg of benzene)

(2.8 - 5.5) = (-4.3) x molality

molality = 0.6279 mole/kg

0.6279 = mole of compound/(20 x 10^-3)

mole of compound = 0.01256 mole

mole (n) = mass (m) divided by Molar mass (Mm)

Molar mass = mass of compound / mole of compound

m/n = 1.6/0.01256 = 127.39 g/mole

8

explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

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in chemistry, a solution’s concentration is how much of a dissolvable substance, known as a solute, is mixed with another substance, called the solvent. the standard formula is c = m/v, where c is the concentration, m is the mass of the solute dissolved, and v is the total volume