Which of the following is correctly ranked in order of increasing bond polarity? o-o < o-f cl-s < cl-br al-o < p-o h-h < n-n b-f < c-f f-o < o-o li-f < c-o

O-O<O-F

option 1 is correct.

Explanation: The bond polarity can be explained on the basis electronegative difference between the atoms.

Greater the electronegativity difference between the two atoms in a bond greater is the polarity of the bond.

Electronegativity difference of a bond between two atoms =EN of atom having higher electronegativity- EN of atom having lower electronegativity

Likewise we can calculate the electronegativity difference for the following bonds and estimate there bond polarities.

1.EN[O-O]=EN(O)-EN(O)=(3.44)-(3.44)=0

EN[O-F]=EN(F)-EN(O)=(3.98)-(3.44)=0.54

So the bond polarity of O-F is more than O-O as it has more electronegativity difference. These two species are correctly arranged as O-O<O-F

2.EN[Cl-S]=EN(S)-EN(Cl)=(3.16)-(2.58)=0.58

EN[Cl-Br]=EN(Cl)-EN(Br)=(3.16)-(2.96)=0.20

So the bond polarity of Cl-S is more than Cl-Br as it has more electronegativity difference. These two species are incorrectly arranged as Cl-S>Cl-Br.

3. EN[Al-O]=EN(O)-EN(Al)=(3.44)-(1.61)=1.83

EN[P-O]=EN(O)-EN(P)=(3.44)-(2.19)=1.25

So the bond polarity of Al-O is more than P-O as it has more electronegativity difference. These two species are incorrectly arranged as Al-O>P-O.

4.EN[H-H]=EN(H)-EN(H)=(2.2)-(2.2)=0

EN[N-N]=EN(H)-EN(N)=(3.04)-(3.04)=0

The electronegativity difference for both the bonds is 0 hence both the bonds would not have any polarity. Hence the mentioned order is incorrect.  

5. EN[B--]=EN(F)-EN(B)=(3.98)-(2.04)=1.94

EN[C-F]=EN(F)-EN(C)=(3.98)-(2.55)=1.43

So the bond polarity of B-- is more than C-F as it has more electronegativity difference. These two species are incorrectly arranged as B-->C-F

6. EN[Li-F]=EN(F)-EN(Li)=(3.98)-(0.98)=3.0

EN[C-O]=EN(O)-EN(C)=(3.44)-(2.55)=0.89.

So the bond polarity of Li-F is more than C-O as it has more electronegativity difference. These two species are incorrectly arranged as Li-F>C-O

7. EN[F-O]=EN(F)-EN(O)=(3.98)-(3.44)=0.54

EN[O-O]=EN(O)-EN(O)=(3.44)-(3.44)=0

So the bond polarity of F-O is more than O-O as it has more

electronegativity difference. So it is incorrectly arranged.

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.

since electrons are negative the answer is neagtaive