If the activation energy for a given compound is found to be 42.0 kj/mol, with a frequency factor of 8.0 × 1010 s-1, what is the rate constant for this reaction at 298 k?

3480s⁻¹

Explanation:We can solve the following problem using the Arrhenius equation.

Arrhenius equation is given by:

A=Pre-exponential factor or frequency factor

Ea=Activation energy

R=Ideal gas constant

T=Temperature

K=Rate constant

From the Arrhenius equation we can see that  the rate constant K is related with the activation energy and frequency factor.

In the question we are given with the following data:

Ea=42KJ/mol=42x 1000 J/mol

A=8.0×10¹ per second

T=298K

R=8.314J/K mol

when we substitute these given values in Arrhenius equation

K=3480s⁻¹

The value of rate constant obtained is 3480s⁻¹.

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it is a good conductor

explanation: