Use the reactions below and their equilibrium constants to predict the equilibrium constant for the reaction 2a(s)⇌3d(g). a(s) ⇌ 12 b(g)+c(g), k1=0.0334 3d(g) ⇌ b(g)+2c(g), k2=2.35

Answer : The equilibrium constant for the reaction will be,

Explanation :

The following equilibrium reactions are :

(1)          

(2)            

The final equilibrium reaction is :

Now we have to calculate the value of for the final reaction.

First we have to multiply equation (1) by 2 that means we are taking square of equilibrium constant 1 and reverse the equation 2 that means we are dividing equilibrium constant 2, we get the final equilibrium reaction and the expression of final equilibrium constant is:

Now put all the given values in this expression, we get :

Therefore, the value of for the final reaction is,

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