Chemistry, 19.07.2019 20:10 laurielaparr2930

300. ml of a 3.0 m aqueous solution of iron (iii) chloride is mixed with 353 grams of a 33.3 mass % solution of silver (u) nitrate and water. 267 grams of a solid precipitate forms. what is the percent yield of the reaction assuming that the solubility of the solid precipitate in water is negligible.

Answers: 2

Show answers

Answers

Answer from: fatty18

26.9%

Explanation: The balanced equation for the reaction of Iron(III)chloride with silver nitrate is:

$FeCl_3(aq)+3AgNO_3(aq)\rightarrow Fe(NO_3)_3(aq)+3AgCl(s)$

From given information, 300.0 mL of 3.0 M aqueous solution of Iron(III)chloride is mixed with 353 grams of 33.3% by mass solution of silver nitrate and water.

From this given information we will calculate the moles of each reactant.

mL of Iron(III)chloride are converted to L and then multiplied by molarity to get its moles.

$300.0mL(\frac{1L}{1000mL})(\frac{3.0mol}{1L})$

= 0.9 moles of Iron(III)chloride

33.3% by mass solution of silver nitrate means 33.3 grams of it are present in 100 grams of solution. We can calculate the grams of silver nitrate present in 353 grams of solution.

$353gSolution(\frac{33.3gAgNO_3}{100gSolution})$

= 117.549 g of silver nitrate

Molar mass of silver nitrate is 169.87 gram per mol. Let's divide the grams by molar mass to calculate its moles.

$117.549g(\frac{1mol}{169.87g})$

= 0.692 moles of silver nitrate

From balanced equation, Iron(III)chloride and silver nitrate react in 1:3 mol ratio. Moles of silver nitrate are less than moles of Iron(III)chloride which clearly indicates that silver nitrate is limiting reactant.

Since, there is 3:3 that is 1:1 mol ratio between silver nitrate and silver chloride, 0.692 moles of silver chloride(precipitate) will form.

Molar mass of AgCl is 143.32 gram per mol. Multiply the moles by molar mass to calculate the grams of AgCl formed.

$0.692molAgCl(\frac{143.32g}{1mol})$

= 99.2 grams

From calculations, theoretical yield is 99.2 grams. The actual yield is given as 267 grams which is not looking good. Actual yield is always less than theoretical yield. It would be making more sense if the actual yield is 26.7 grams. So, if we do the calculations by taking the actual yield as 26.7 grams then the percent yield is calculated as:

percent yield = $(\frac{26.7}{99.2})*100$

= 26.9%

So, the percent yield of the reaction will be 26.9%.

Answer from: Quest

I’m guessing you’re more alert to yourself or your surroundings if you’re more concentrated

Answer from: Quest

Yes i think so not 100 percent sure though

Another question on Chemistry

Chemistry, 22.06.2019 18:00

Heat is the total potential energy of a substance that can be transferred. true false

Answers: 1

Answer

Chemistry, 22.06.2019 18:10

The atom fluorine generally will become stable through the formation of an ionic chemical compound by accepting electron(s) from another atom. this process will fill its outer energy level of electrons.

Answers: 1

Answer

Chemistry, 22.06.2019 21:30

Harry lives in a city, and he has a lung condition known as asthma. on certain days, harry has to stay inside because pollutants in the air make it difficult for him to breathe. which of these pollution sources are nonpoint sources that might bother harry if he goes outside? choose the two that apply.

Answers: 3

Answer

Chemistry, 23.06.2019 00:00

What atom has the largest atomic radius

Answers: 2

Answer

You know the right answer?

300. ml of a 3.0 m aqueous solution of iron (iii) chloride is mixed with 353 grams of a 33.3 mass %...

Questions