Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other has carbon tetrachloride as the solvent. determine the molal concentration, (or and boiling point, . solvent normal boiling point (∘ (∘/ benzene 80.1 2.53 carbon tetrachloride 76.8 5.03

Hey there!:

Δt =  m * Kf

Boiling point of a solution =>  Boiling point + Δt ( Kc * m )

Boiling point of benzene solution => 80.1 + 2.53 m

Boiling point of CCl₄ solution => 76.8 +5.03 m

Since the boiling points are the same 80.1 + 2.53 m = 76.8 +5.03 m

3.3 = 2.5 m

m =  3.3 / 2.5 => 1.32 moles of solute per kg of solvent

Bp =   80.1 + 2.53 * 1.32 => 83.4396 ºC

Hope this helps!

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