What is the pressure of 0.540 mol of an ideal gas at 35.5 l and 223 k

Explanation:

1) Data:

a) n = 0.540 mol

b) V = 35.5 liter

c) T = 223 K

2) Formula:

Where,

3) Calculations:

      PV = nRT ⇒ P = nRT/V

       P = 0.540 mol × 0.08206 atm-liter/K-mol × 223 K / 35.5 liter

       P = 0.0443 atm (you must use 3 significant figures).

a graduated cylinder.

explanation:

i think it is true since you can test the answer and can use observations to complete it.