The reaction 2no2 → 2no + o2 obeys the rate law: rate = 1.4 x 10-2[no2]2 at 500 k . what would be the rate constant at 191 k if the activation energy is 80. kj/mol? this is a second order reaction, giving k the units of m-1s-1 this will not change with the change in temperature. do not include units in your answer. exponential numbers need to be entered like this: 2 e-1 means 2 x 10-1.