Use plank’s constant, 6.626  ×  10-34, to solve the following:
what is the amount of energy carried by a photon that has a frequency of 5.71  ×  1014hz?
question 15 options:
525 nm
3.78  ×  10-19  j
1.14  ×  10-8  j
8.62  ×  1047  j/s

B. J

Explanation:

Energy (E) = Planck's constant (h) × Frequency (ν)

1 Hertz = 1  

So Hertz and are equal

(s and gets cancel as both are in the numerator leaving behind Joules)

(Moving the decimal point to the left one place power of 10 increases from -20 to - 19)

J (Answer)

- lead + phosphoric acid = hydrogen + lead(ii) phosphate