Cyclopentadiene is unusually acidic for a hydrocarbon. why? cyclopentadiene is aromatic. the conjugate base of cyclopentadiene is aromatic. cyclopentadiene is an unstable diradical. the conjugate base of cyclopentadiene is an unstable diradical.

The unusual acidity of cyclopentadiene is because of the fact that on losing a proton it can attain aromaticity and be quite stable.

The conjugate base of cyclopentadiene is aromatic.

Explanation:

The acidity of a molecule can be explained in terms of stability of its conjugate base anion.

So greater the stabilization of conjugate base anion greater the acidity of the molecule.

In case of cyclopentadiene as soon as we abstract a proton from the sp³ hybridised carbon atom ,it  leads to a formation of a carbanion and hybridisation of the carbon atom changes from sp³ to sp²and hence now the molecular becomes planar. The negative charge on the carbanion  is in the p-orbital and hence  now this negative charge can be in conjugation with the 4π electrons available in the system  and be delcoalized over the whole ring  and now there are 6π electrons available.

Intially the number of π eletcrons=4

after proton abstraction number of π eletcrons=6

The rule for aromaticity comes from the Huckels rule that the system must have 4n+2π electrons.

After the deprotonation molecule has 4n+2π electrons with n=1.

This delocalization of the negative charge over the whole ring leads to increment in the π electrons of the molecule and the molecule from being anti-aromatic becomes aromatic.

So the attainment of aromaticity after losing a proton leads to a high acidity of cyclopentadiene.

Kinly find in attachment the structure and electron delocalisation of π electrons.

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8