How many moles of fe304 are required to supply enough iron to prepare 0.171 mol fe203?

0.114 moles

Explanation:

Calculate available moles of Fe:

0.171 mol Fe₂O₃ × (2 mol Fe / mol Fe₂O₃) = 0.342 mol Fe

Now calculate moles of Fe₃O₄ needed:

0.342 mol Fe × (1 mol Fe₃O₄ / 3 mol Fe) = 0.114 mol Fe₃O₄

20 drops hope this