Energy of sublimation of na(s) = 97 kj/mol bond energy of hbr = 363 kj/mol ionization energy of na(g) = 496 kj/mol electron affinity of br(g) = –324 kj/mol lattice energy of nabr(s) = –781 kj/mol bond energy of h2 = 432 kj/mol calculate the net change in energy for the following reaction: 2na(s) + 2hbr(g) → 2nabr(s) + h2(g)

Calculate the number of molecules present in 0.750 mol of mgo.

Calculate the ratio of h+ ions to oh– ions at a ph = 7. find the concentration of h+ ions to oh– ions listed in table b of your student guide. then divide the h+ concentration by the oh– concentration. record this calculated ratio in table a of your student guide. compare your approximated and calculated ratios of h+ ions to oh– ions at a ph = 7. are they the same? why or why not? record your comparison in table a. what is the concentration of h+ ions at a ph = 7? mol/l what is the concentration of oh– ions at a ph = 7? mol/l what is the ratio of h+ ions to oh– ions at a ph = 7? : 1

What is the percentage of hydrogen in nitrogen trihydride