The energy required to remove the third electron from an atom would be called the a. tertiary removal energy b. atoms cannot lose 3 electrons. c. teriary ionization energy d. third ionization energy

D. Third ionization energy

Explanation:

Ionization energy describes the energy enough to remove the valence electrons from atoms in a ground state. It is a measure of the readiness of an atom to lose an electron. The lower this value, the easier it is for an atom to lose electrons and vice versa.

The first ionization energy is the energy needed to remove the most loosely bound electron of an atom. The third ionization energy would be the energy required to remove the third electron from an atom.

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

58750.08068 is the answer i think