At 90°c the vapour pressure of l,2·dimethylbenzene is 20kpa and that of 1,3-dimethylbenzene is 18 kpa. w'hat is the composition of the vapour of an equimolar mixture of the two components?

19kPa

Explanation:

the total pressure is given by

The pressure

similarly

for equilibrium process let us consider both have one mole

so

similarly

so

so total pressure=10+9=19 kPa

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.

12 is it do you think so