Calculate the percent ionization of formic acid (hco2h) in a solution that is 0.125 m in formic acid. the ka of formic acid is 1.77 ⋅ 10-4. calculate the percent ionization of formic acid (hco2h) in a solution that is 0.125 m in formic acid. the ka of formic acid is 1.77 10-4. 0.859 0.0180 3.79 2.25 ⋅ 10-5 6.94

Percent ionization of HCOOH is 3.69%

Explanation:

To calculate percent ionization of HCOOH, we have to construct an ICE table to determine changes in concentrations at equilibrium.

    I:                0.125                                       0             0

    C:                -x                                           +x            +x

    E:              0.125-x                                     x              x

species inside third bracket represent equilibrium concentrations

So,      

   or,  

   or,

or, M

So,

Percent ionization of formic acid  = = = 3.69%

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml