At 900.0 k, the equilibrium constant (kp) for the following reaction is 0.345. 2so2 + o2 (g) →2 so3 (g) at equilibrium, the partial pressure of so2 is 36.9 atm and that of o2 is 16.8 atm. the partial pressure of so3 is atm.

Answer : The partial pressure of is, 88.84 atm

Solution :  

The given equilibrium reaction is,

= 36.9 atm

= 16.8 atm

The expression of will be,

Now put all the values in this expression, we get

Therefore, the partial pressure of is, 88.84 atm

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