The decomposition of nitrogen dioxide to nitrogen monoxide and oxygen gas is a second order process as suspected in the previous question. one would expect the second half-life of this reaction to be the first half-life of this reaction.

Explanation:

For the given reaction

Now, expression for half-life of a second order reaction is as follows.

                      ....... (1)

Second half life of this reaction will be . So, expression for this will be as follows.

          =  ...(2)

where is the final concentration that is, here and is the initial concentration.

Hence, putting these values into equation (2) formula as follows.

        =

                      =     ...... (3)

Now, dividing equation (3) by equation (1) as follows.

            =                  

                                    = 3

or,                       = 3    

Thus, we can conclude that one would expect the second half-life of this reaction to be three times the first half-life of this reaction.

the right answer is c i just did the question.

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explanation: