Chemistry, 01.08.2019 06:10 mallyosburn

Identify the oxidized substance and the reduced substance in the redox reaction. mg(s)+cl2(g)⟶mg2+(aq)+2cl−(aq) which substance gets oxidized? mg cl2 cl− mg2+ which substance gets reduced?

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Answer from: Jakeandjenn21

Mg (s) is the oxidized substance and $Cl_{2}$ (g) is the reduced substance

Explanation:

If oxidation number of a substance increases then that substance is being oxidized. This is due to release of electron from that substance.

If oxidation number of a substance decreases then that substance is being reduced. This is due to consumption of electrons by that substance.

Element oxidation number

Mg(s) 0

$Cl_{2}$ 0 (Cl)

$Mg^{2+}$ +2 (Mg)

$Cl^{-}$ -1 (Cl)

So oxidation number of Mg increases by +2 which occurs due to release of two electrons from Mg (s). Hence Mg (s) is being oxidized.

And oxidation number of Cl decreases by -1 which occurs due to consumption of one electron by $Cl_{2}$ (g). Hence $Cl_{2}$ (g) is being reduced.

Answer from: Quest

the correct answer would be b. amelia, because the particals of gas move really fast (charged particals) and gas also has a lot of room (particals move independently) so the only answer that has both of those is amelia's.

Answer from: Quest

Answer: 1.0 × 10⁻⁵ msolution: as we know ph is given as, ph = -log [h⁺]and, [h⁺] = 10^-ph (1)putting value of ph in eq. 1, [h⁺] = 10⁻⁵ [h⁺] = 1.0 × 10⁻⁵ m

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Identify the oxidized substance and the reduced substance in the redox reaction. mg(s)+cl2(g)⟶mg2+(a...

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