What mass of oxygen can be obtained from heating 258.77 g of potassium chlorate?

101.35 g

Explanation:

The balanced equation for the reaction is:

2KClO3 > 2KCl  + 3O2

So 2 moles of KClO3 produces 3 moles of Oxygen

Using the molar masses:

245.09 g KClO3 produces 95.994 g of  oxygen.

258.77 g produces 95.994 * 258.77 / 245.09 = 101.35 g (answer).

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole