Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia. n2(g)+3h2(g)⟶2nh3(g) assume 0.140 mol n2 and 0.459 mol h2 are present initially. after complete reaction, how many moles of ammonia are produced?

moles of ammonia produced = 0.28 moles

Explanation:

The reaction is

As per equation, one mole of nitrogen will react with three moles of hydrogen to give two moles of ammonia

So 0.140 moles of nitrogen will react with = 3 X 0.140 moles of Hydrogen

             = 0.42 moles of hydrogen molecule.

this will give 2 X 0.140 moles of ammonia = 0.28 moles of ammonia

the moles of ammonia produced = 0.28 moles

Here the nitrogen is limiting reagent.