When octane (c8h18) is burned in a particular internal combustion engine, the yield of carbon dioxide is 93%. what mass of carbon dioxide will be produced in this engine when 15.0 g of octane (mw = 114.0 g/mol) is burned with 15.0 g of oxygen gas (mw = 32.0 g/mol)? 2c8h18 + 25 o2 --> 16 co2 + 18 h2o
a.12g b.13g c.21g d.43g e.54g

The correct answer is option a.

Explanation:

Moles of octane =

Moles of oxygen gas =

According to reaction, 25 moles of oxygen reacts with 2 moles of octane.

Then 0.46875 moles of oxygen will react with:

of octane

Oxygen is present in limited amount. Hence, limiting reagent.

According to reaction , 25 moles of oxygen gives 16 moles of carbon-dioxide.

Then 0.46875 moles of oxygen will give:

of carbon-dioxide

Mass of 0.3 moles of carbon-dioxide:

0.3 g × 44 g/mol = 13.2 g

Theoretical yield = 13.2 g

Experimental yield = x

Percentage yield of carbon dioxide = 93 %

x =12.27 g ≈ 12 g

12 grams of carbon dioxide will be produced in this engine .

answer: the primary difference between a hypothesis and a theory is that b hypothesis is falsifiable, but a theory has been proven to be correct. theory is an explanation of something that is happening but hypothesis is a guess of something that can happen

explanation: