Glucose, c6h12o6, is used as an energy source by the human body. the overall reaction in the body is described by the equation c6h12o6(aq)+6o2(g)⟶6co2(g)+6h2o(l)
calculate the number of grams of oxygen required to convert 53.0 g of glucose to co2 and h2o.

Answer : The mass of oxygen required are, 56.448 grams

Explanation : Given,

Mass of glucose = 53 g

Molar mass of glucose = 180.156 g/mole

Molar mass of = 32 g/mole

First we have to calculate the moles of .

Now we have to calculate the moles of .

The balanced chemical reaction will be,

From the balanced chemical reaction, we conclude that

As, 1 mole of react with 6 moles of

So, 0.294 mole of react with mole of

Now we have to calculate the mass of .

Therefore, the mass of oxygen required are, 56.448 grams

it would be a gas formation

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3