The solubility product, ksp, of ca (po4 is 2.0 x 10-32. calculate its solubility (in g/l) (a) (4 points) in pure water (b) (4 points) in a 0.150 m solution of cach

a) S = 1.7099 E-11 g/L

b) S = 8.88 E-31 g/L

Explanation:

a) in water:

solubility:       S               S             2S

Ksp = [ Ca²+ ] * [ PO4²-]² = ( S ) * ( 2S )² = 4S³ = 2.0 E-32

⇒ S = ∛ (2.0 E-32 / 4) = 1.7099 E-11 g/L

b) 0.150 M sln CaCH:

          0.15       0.15        0.15

Ksp = ( S ) * ( 2S + 0.15 )² we despise solubility as adding

⇒ Ksp = ( S ) * ( 0.15 )² = 2.0 E-32

⇒ S = 2.0 E-32 / 0.0225 = 8.88 E-31 g/L

answer: mercury

explanation:

the answer to this question is 3.