a solution contains 10.0 g pentane, c5h12, 20.0 g hexane, c6h14, and 10.0 g benzene, c6h6. what is the mole fraction of hexane?
a) 0.303
b) 0.471
c) 0.433
d) 0.362
e) 0.335

b) 0.47

Explanation:

MwC5H12 = 72.15g/mol

⇒mol C5H12 = (10.0)*(mol/72.15)=0.1386molC5H12

MwC6H14=86.18g/mol

⇒molC6H14=(20.0)*(mol/86.18)=0,232

MwC6H6=78.11g/mol

⇒molC6H6=(10.0)*(mol/78.11)=0.128molC6H6

XC6H14=(0.232)/(0.1386+0.232+0,128)=0.465≅0.47

Idk the answer sorry

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