According to the following reaction: khp+ naoh> nakp+ h20 used instead of glucose? water? sea water? what is the concentration of the naoh if it took 42.52 ml to titrate 0.835 g of khp? (mm khp 204.2 g/mol)

The molarity of NaOH solution is 0.096 M.

Explanation:

To calculate the number of moles, we use the equation:

Given mass of KHP = 0.835 g

Molar mass of KHP = 204.2 g/mol

Putting values in above equation, we get:

For the given chemical reaction:

By Stoichiometry of the reaction:

1 mole of KHP reacts with 1 mole of NaOH.

So, 0.00408 moles of KHP will react with = of NaOH.

To calculate the molarity of NaOH, we use the equation:

We are given:

Moles of NaOH = 0.00408 moles

Volume of solution = 42.52 mL = 0.04252L      (Conversion factor:  1L = 1000 mL)

Putting values in above equation, we get:

Hence, the molarity of NaOH solution is 0.096 M.

i need mutiple choices

the answer is option a.