Consider the following redox equation mn(oh)2(s) + mno4 –(aq)  mno42 –(aq) (basic solution) when the equation is balanced with smallest whole number coefficients, what is the coefficient for oh –(aq) and on which side of the equation is oh –(aq) present?

Answer : The balanced chemical equation is,

The coefficient for is, 4 and on reactant side of the equation is present.

Explanation :

Rules for the balanced chemical equation in basic solution are :

First we have to write into the two half-reactions.Now balance the main atoms in the reaction.Now balance the hydrogen and oxygen atoms on both the sides of the reaction.If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the more number of oxygen are present.If the hydrogen atoms are not balanced on both the sides then adding hydroxide ion at that side where the less number of hydrogen are present.Now balance the charge.

The half reactions in the basic solution are :

Reduction : ......(1)

Oxidation : .....(2)

Now multiply the equation (1) by 2 and then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

Thus, the coefficient for is, 4 and on reactant side of the equation is present.

Google it that might work

We can’t you if you only tell us that you have to show us what the answers are