Acube made of platinum (pt) has an edge length of 1.0 cm. (a) calculate the number of pt atoms in the cube. (b) atoms are spherical in shape. therefore, the pt atoms in the cube cannot fill all the available space. if only 74 percent of the space inside the cube is taken up by pt atoms, calculate the radius in picometers of a pt atom. the density pt is 21.45 g/cm3, and the mass of a single pt atom is 3.240 x 10^-22 g. (the volume of a sphere of radius r is 4/5ïr^3).

a)The total number of platinum atoms are .

b)The radius of a Pt atom is 138.7 pm.

Explanation:

a) Let the total number of platinum atoms be x

And mass of x atoms of platinum be m

Edge length of platinum cube ,s= 1.0 cm

Volume of the cube =

Density of the platinum cube =

Mass = Density × Volume

Mass of an atom of platinum =

b) If only 74 percent of the space inside the cube is taken up by Pt atoms.

Volume occupied by platinum atoms = 74% of

Volume occupied by atoms is.

The radius of a Pt atom is 138.7 pm.

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24