Below is a proposed mechanism for the decomposition of h2o2. h2o2 + i– → h2o + io– slow h2o2 + io– → h2o + o2 + i– fast which of the following statements is incorrect? a. io– is a catalyst. b. the reaction is first-order with respect to [i–]. c. the reaction is first-order with respect to [h2o2]. d. the net reaction is 2h2o2 → 2h2o + o2. e. i– is a catalyst.

Option (d) is the correct answer.

Explanation:

The given equations as as follows.

                  (slow)

Therefore, overall reaction equation will be as follows.

So, cancelling the spectator ions then the equation will be as follows.

As, it is known that slow step of a reaction is the rate determining step. Therefore, rate law for the slow step will be as follows.

                 Rate law =

Hence, the reaction is first order with respect to and it is also first order reaction with respect to .

Also, acts as a catalyst in the reaction.

Thus, we can conclude that the incorrect statement is is a catalyst.

the answer for sodium is 0.186

the answer for rubidium is 0.251

wher is the rest of the question