The complete combustion of octane, c8h18, a component of gasoline, proceeds as follows: 2c8h18(l)+25o2(g)→16co2(g)+18h2o(g) relevant volumetric equivalencies 1 gal = 3.785 l 1 l = 1000 ml
part a how many moles of o2 are needed to burn 1.35 mol of c8h18?

Moles of oxygen needed to burn given amount of octane is 16.875 moles.

Explanation:

We are given:

Moles of octane burned = 1.35 mol

For the given chemical reaction:

By Stoichiometry of the reaction:

When 2 moles of octane is burnt, then 25 moles of oxygen are needed

So, when 1.35 moles of octane is burned, then = of oxygen are needed.

Hence, moles of oxygen needed to burn given amount of octane is 16.875 moles.

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

a small container that holds a source of energy a solar cell that captures light energy and converts it into electricity a voltaic cell that uses the oxidation of a fuel to produce electricity

explanation: