Chemistry, 23.08.2019 05:10 Kjswagout5052

What is the energy released in the fission reaction 1 0 n + 235 92 u → 131 53 i + 89 39 y + 16 1 0 n 0 1 n + 92 235 u → 53 131 i + 39 89 y + 16 0 1 n ? (the atomic mass of 131 i 131 i is 130.9061246 u and that of 89 y 89 y is 88.9058483 u)

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Answer from: jchavez0790

The energy released in the given nuclear reaction is 94.99 MeV.

Explanation:

For the given nuclear reaction:

$_{92}^{235}\textrm{U}+_0^1\textrm{n}\rightarrow _{53}^{131}\textrm{I}+_{39}^{89}\textrm{Y}+16_{0}^1\textrm{n}$

We are given:

Mass of $_{92}^{235}\textrm{U}$ = 235.043924 u

Mass of $_{0}^{1}\textrm{n}$ = 1.008665 u

Mass of $_{53}^{131}\textrm{I}$ = 130.9061246 u

Mass of $_{39}^{89}\textrm{Y}$ = 88.9058483 u u

To calculate the mass defect, we use the equation:

$\Delta m=\text{Mass of reactants}-\text{Mass of products}$

Putting values in above equation, we get:

$\Delta m=(m_U+m_{n})-(m_{I}+m_{Y}+16m_{n})\\\\\Delta m=(235.043924+1.008665)-(130.9061246+88.9058483+16(1.008665))=0.1019761u$

To calculate the energy released, we use the equation:

$E=\Delta mc^2\\E=(0.1019761u)\times c^2$

$E=(0.1019761u)\times (931.5MeV)$ (Conversion factor: 1u=931.5MeV/c^2 )

E=94.99MeV

Hence, the energy released in the given nuclear reaction is 94.99 MeV.

Answer from: Quest

Answer: abeexplanation:

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.

Answer from: Quest

Hairy thick gross thing? idk

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What is the energy released in the fission reaction 1 0 n + 235 92 u → 131 53 i + 89 39 y + 16 1 0 n...

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