Water is being pumped from the bottom of a well 150 feet deep at a rate of 200 gal/hour into a vented storage tank 30 feet above the ground. to prevent freezing in the winter, a small heater puts 30,000 btu/hour into the water during its transfer from the well to the storage tank. heat is lost from the whole system at a constant rate of 25,000 btu/hr. what is the rise or fall in the temperature of the water as it enters the storage tank, if the well ware is at 35°f? a 2 hp pump is being used to pump the water. the pump efficiency is 55 percent. evaluate any properties of water at 35°f.

Explanation:

As the given data is as follows.

        Height, H = 150 feet

 Heat gain = 30,000 BTU/hr,  and  Heat loss = 25000 BTU/hr

  m = mass of water heated = 700 gallons = 5810 lbs

is the heat capacity of water = 1 BTU/lb (given)

      = temperature difference =

Heat energy required to heat 700 gal can be calculated as follows:

    Heat Required =

Thus, water rises till .

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.