In making wine, glucose (c6h12o6) is fermented to produce ethanol (c2h5oh) and carbon dioxide (co2), according to the following reaction. c6h12o6 → 2 c2h5oh + 2 co2 (a) if the fermentation reaction starts with 68.0 g glucose, what is the theoretical yield of ethanol (in grams)? g (b) if 13.0 g ethanol is produced, what is the percent yield of this reaction?

a) Theoretical yield of ethanol = 34.778 g

b) % yield of ethanol = 37.38%

Explanation:

a)

C6H12O6 → 2 C2H5OH + 2 CO2

Molar mass of glucose = 180.156 g/mol

Molar mass of ethanol = 46.07 g/mol

amount of glucose taken = 68.0 g

No. of mole = Amount of substance in g/Molar mass

[text]No. of mole = \frac{68.0\;}{180.156\; g/mol} =0.37745 mol[\text]

from reaction stoichiometry, one mole of glucose fermented two form 2 mole of ethanol.

therefore, 0.37745 mol of glucose will form 0.37745*2 moles of ethanol.

No. of moles of ethanol formed = 0.7549 mol

theoretical yield of ethanol = 0.7549 x 46.07 = 34.778 g

b)

Actual yield = 13.0 g

Theoretical yield = 34.778 g

                    = 37.38%

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

i think it is true since you can test the answer and can use observations to complete it.