Seawater is typically 3.5% salt and has a density of 1.03 g/ml. how many grams of salt would be needed to prepare enough seawater solution to completely fill a 62.5 l tan

Amount of salt needed is around 2.3*10³ g

Explanation:

The salt content in sea water = 3.5 %

This implies that there is 3.5 g salt in 100 g sea water

Density of seawater = 1.03 g/ml

Volume of seawater = volume of tank = 62.5 L = 62500 ml

Therefore, the amount of seawater required is:

The amount of salt needed for the calculated amount of seawater is:

the potential energy of the reactants is 200j.

from the energy diagram, the energy of the product formed is 350j; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.