505 grams of koh are required to completely react with 4.50 mole of sulfuric acid. how many moles of products are produced?

Answer : The moles of products and are, 4.50 and 9 moles.

Explanation : Given,

Mass of water = 5.2 g

Molar mass of water = 18 g/mole

Molar mass of = 32 g/mole

The balanced chemical reaction will be,

First we have to calculate the moles of KOH.

Now we have to calculate the limiting and excess reactant.

From the balanced reaction we conclude that

As, 1 mole of react with 2 mole of

So, 4.50 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of products and .

From the balanced chemical reaction, we conclude that

As, 1 moles of react to give 1 moles of

So, 4.50 moles of react to give 4.50 moles of

and,

As, 1 moles of react to give 2 moles of

So, 4.50 moles of react to give moles of

Therefore, the moles of products and are, 4.50 and 9 moles.

14,16 18 reacts with group