25 ml of 0.10 m aqueous acetic acid is titrated with 0.10 m naoh(aq). what is the ph after 30 ml of naoh have been added?

Answer : The pH after 30 mL of NaOH added will be 11.96

Explanation : Given,

Concentration of acetic acid = 0.10 M

Volume of acetic acid = 25 mL = 0.025 L    (conversion used : 1 L = 1000 mL)

Concentration of NaOH = 0.10 M

Volume of NaOH = 30 mL = 0.030 L

First we have to calculate the moles of and .

The balanced chemical reaction is,

Initial moles      0.0025        0.0030               0

At eqm. moles       0        (0.0030-0.0025)   0.0025

                                          = 0.0005

Now we have to calculate the hydroxide ion concentration.

Now we have to calculate the hydrogen ion concentration.

Now we have to calculate the pH.

Therefore, the pH after 30 mL of NaOH added will be 11.96

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

answer seismograph;