1.calculate the end velocity of a rocket that traveled 16km in 2 seconds. distance time 2.calculate the rockets acceleration m with a start velocity of 0m/s and the end velocity from #1 for 10 seconds. (final velocity- start velocity) time * be sure to include units!

Explanation:

1. The rocket covered a distance,

Time taken, t = 2 s

The velocity of rocket is given by total distance over total time. It is given by :

v = 8000 m/s

2. Initial velocity of the rocket, u = 0

Final velocity of the rocket in part 1, v = 8000 m/s

Time taken, t = 10 s

Acceleration of rocket is given change in speed divided by total time. It is given by :

So, the acceleration of the rocket is . Hence, this is the required solution.

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

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