The p k a of acetic acid is 4.76, and the p k a of trichloroacetic acid, which is used to remove warts, is 0.7. calculate the dissociation constant of each acid. which is the stronger acid?

CH3COOH: Ka = 1.74 E-5

CCL3COOH: Ka = 0.1995

⇒ K CCl3COOH >> K CH3COOH ∧  pKCCl3COOH < pKCH3COOH;  the higher pKa the extent of the dissociation is less; therefore CCl3COOH is a stronger acid than CH3COOH

Explanation :

CH3COOH:

pKa = 4.76 = - Log Ka

⇒ Ka = 1.74 E-5

CCl3COOH:

∴ pKa = 0,7 = -log Ka

⇒ Ka = 0.1995

jdjxnbfb

explanation:

jjfnc fdnxnxx

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.