Calculate the percent ionization of nitrous acid in a solution that is 0.222 m in nitrous acid (hno3) and 0.278 m in potassium nitrite (kno2). the acid dissociation constant of nitrous acid is 4.50 x 10-4 a) 55.6 b) 0.162 c) 15.5 d) 2.78 * 10-3

Explanation:

Concentration of is 0.278 M and it is completely ionized into and .

This means that = = 0.278 M

It is given that concentration of is 0.222 M.

As is a weak acid. Therefore, its dissociation will be as follows.

Initially :    0.222 M            0        0.278 M

Change :    - x                    +x           +x

Equilibrium : 0.222 M - x    x         0.278 M + x

Therefore, dissociation constant for this reaction will be as follows.

Hence, putting the given values into the above formula as follows.

                          x = 0.00036

As, is 0.00036 M. Therefore, percentage ionization of will be calculated as follows.

              % ionization of =

                               =

                               = 0.16 %

Thus, we can conclude that % ionization of is 0.16%.

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.