Sc ample of argon a - 6 12 and 780 on what is the volume of this argas 5.79 what is the the temperature s a of o: os occupying 200 l at 100 ste? gas dalton's law of partial pressures-5.83, 5.05, 5.67 5.83 state dalton's law in words. 0.05 a gas mixture has three components n f and he. their partial pressures are 0.40 atm, 0.16 atm, and 0.78 atm, respectively. what is the pressure of the gas mixture? 5.87 a gas mixture has a total pressure of 0.56 atm and consists of he and ne. if the partial pressure of the he in the mixture is 0.27 atm, what is the partial pressure of the ne in the mixture?

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole