Calculate the mass of vanadium(v) oxide (v2o5) that contains a million (1.0 *10^6) vanadium atoms. be sure your answer has a unit symbol if necessary, and round it to 3 significant digits.

Answer : The mass of vanadium(V) oxide will be

Explanation : Given,

Number of atoms of =

Molar mass of = 181.88 g/mole

In , there are 2 atoms of vanadium and 5 atoms of oxygen.

First we have to determine the moles of .

As, number of vanadium atom present in 1 moles of

So, number of vanadium atom present in moles of

Now we have to determine the mass of .

Therefore, the mass of vanadium(V) oxide will be

Explanation:

It is known that molar mass of is 181.88 g/mol.

We will calculate the number of vanadium atoms present in 1 mole of as follows.

                  atoms

                  = atoms

Therefore, mass of which contains atoms of vanadium = Molar mass of = 181.88 g/mol.

Hence, we will calculate the mass of that contains vanadium atoms as follows.

              =

Thus, we can conclude that mass of in given situation is g/mol.

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.