Consider the equilibrium of al(oh)3 (s) in water. al(oh)3 (s) = a13+ (aq) + 30h" (aq) how is the solubility of al(oh)3 affected by adding hcl to the solution? does the solid become more or less soluble? explain using equilibrium and the ksp.

Solid become more soluble

Explanation:

The given reaction:

On the addition of HCl to the equilibrium, the equilibrium will shift towards right which means more dissociation of aluminum oxide. This is because the furnished hydroxide ions from aluminum oxide on dissolution now binds with the protons furnished by the acid to form water and thus there become less concentration of the hydroxide ions on the right side and to nullify this effect, the equilibrium will shift in right direction.

Solubility product is defined as the product of the concentration of the ions of the solid. More the solubility product more is the solubility.

Thus, on addition of the acid, the solid become more soluble.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.